Wireshark-dev: Re: [Wireshark-dev] [Wireshark-commits] buildbot failure in Wireshark (developme
On 28-03-2016 15:51, Joerg Mayer wrote:
On Mon, Mar 28, 2016 at 02:26:41PM +0000, buildbot-no-reply@xxxxxxxxxxxxx wrote:
The Buildbot has detected a new failure on builder Ubuntu 14.04 x64 while building wireshark. Full details are available at:
http://buildbot.wireshark.org/wireshark-master/builders/Ubuntu%2014.04%20x64/builds/5897
../../../epan/wslua/taps_wslua.c: In function 'wslua_bacapp_to_table':
../../../epan/wslua/taps_wslua.c:43:93: error: variable 'v' set but not used [-Werror=unused-but-set-variable]
static void wslua_bacapp_to_table(lua_State* L, const void* p) { const bacapp_info_value_t* v; v = (const bacapp_info_value_t*)p; lua_newtable(L);
Buildbot URL: http://buildbot.wireshark.org/wireshark-master/
Buildslave for this Build: ubuntu-14.04-x64
Build Reason: The SingleBranchScheduler scheduler named 'Gerrit' triggered this build
Build Source Stamp: [branch master] 7e5dae90d65ed062f2d01c63174cc1c94850a19a
Blamelist: Jörg Mayer <jmayer@xxxxxxxxx>
BUILD FAILED: failed make distcheck
OK, this is strange: I changed epan/wslua/make-taps.pl to not declare v as _U_ (which
is obviously isn't: it's used in the next statement) and now we get a "set but not used"
warning but not before? Btw, on my Clang (XCode) system I do not get this warning/error.
Ideas what is going on here (compiler bug?)?
The variable is set but not used. Nothing strange about the warning.
