Quoting "Martin Visser" <
martinvisser99@xxxxxxxxx>:
> Juha,
>
> What you are seeing is the RTT for the traffic from the view of the server
> being responded to by the client. I assume from your notes that you are
> capturing traffic at the client end. Every time the server sends a
> non-zero-length TCP payload incrementing the SEQ, it also expects an ACK
> back from the client. Of course the same goes from the client traffic toward
> the server. Even though you are capturing on the client end, it still needs
> to do some processing before it sends the ACK.
>
> The fact that RTT is quantised (at discrete levels) I think is indicative of
> the resolution of the system clock on your machine, and hence the time
> stamp. (There is some incomplete discussion on that here -
>
http://wiki.wireshark.org/Timestamps)
>
> In order to see the RTT graph that corresponds to the response time for
> client requests towards the server, you must select a frame in the TCP
> session that is in that direction. You have selected a frame from server to
> client, just select one going the other direction and then display the RTT
> graph again. You should then get what you expect.
>
> Regards, Martin
>
>
MartinVisser99@xxxxxxxxx
>
>
> On Tue, Jan 20, 2009 at 2:39 AM, Juha Yli-Penttilä <
juha.yli-penttila@xxxxxx
>> wrote:
>
>> Hi all,
>>
>> I captured a log of FTP transfer using EGPRS dial-up connection. The RTT
>> values seem to be too small, because most of the values are < 70ms. In
>> practise these should be something like 200-500ms. The log capturing and FTP
>> client were run on the same computer (another endpoint). Am I doing
>> something wrong or why the RTT estimates are this small? From the figure can
>> also be seen that most of the RTT values are on some certain levels, which I
>> guess should not be the case. Attached TCP RTT graph. Thanks in advance.
>>
>> --
>> Juha Yli-Penttilä
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