Well i did this...but i dont know if it's ideal...i think it would work though....
I synchronized the two computers to a server on the internet before every capture so both have the exact same time.
i have my sniffer in the two computers, the one that sends and the ones that receive.
I created a function in matlab that calculates the difference between those two times...
I am being really carefull when i have a packet lost or things like that....
But probably this can work???? ...
On 13/03/2008, juan.wortley@xxxxxxx <juan.wortley@xxxxxxx> wrote:
Hi Fabiana,
the only way to do that is if you know the time difference
between the machines.
It´s not so easy however if you use windows you could try
synchronizing both endpoints by using:
w32tm /config /manualpeerlist:[IP to synchronize to]
/update /syncfromflags:MANUAL
and
then monitor the time difference with:
w32tm
/stripchart /computer:[IP to synchronize to]
,you
always can have a delay reference by pinging and dividing by 2 the
RTT.
HTH
Juan
so ... it is not reliable if i substract the time i hav in the
client minus the time i have in the server to get my end the end
delay?
On 12/03/2008, Hansang
Bae <hbae@xxxxxxxxxx>
wrote:
Fabiana
moreno wrote:
> Hello there,
>
> I know wireshark is not
able to calculate the end-to-end delay of a
> packet when streaming. I
was just wondering if adjusting the clocks of
> my two
computers(sender and receiver) to the network time protocol and
>
having the sniffer at both ends i could calculate the
end-to-end-delay
> tracing each packet. Does this sound
logical?
>
It is within the limits of
ntp. Unless there is a WAN involved, the
packets are flying
around at an order of magnitude faster than what ntp
can provide (ms
resolution)
--
Thanks,
Hansang
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